Company XYZ know that replacement times for the quartz time pieces it produces are normally distributed with a mean of 15.4 years and a standard deviation of 1.4 years.
Find the probability that a randomly selected quartz time piece
will have a replacement time less than 12.6 years?
P(X < 12.6 years)
If the company wants to provide a warranty so that only 3.2% of
the quartz time pieces will be replaced before the warranty
expires, what is the time length of the warranty?
warranty
A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 120.2-cm and a standard deviation of 2.2-cm.
Find the probability that the length of a randomly selected
steel rod is less than 124.8-cm.
P(X < 124.8-cm) =
A company produces steel rods. The lengths of the steel rods are
normally distributed with a mean of 131.5-cm and a standard
deviation of 0.6-cm.
Find the probability that the length of a randomly selected steel
rod is between 130.8-cm and 133.4-cm.
P(130.8-cm < X < 133.4-cm) =
Company XYZ know that replacement times for the quartz time pieces it produces are normally distributed...
Company XYZ know that replacement times for the quartz time pieces it produces are normally distributed with a mean of 11 years and a standard deviation of 1.8 years. a) Find the probability that a randomly selected quartz time piece will have a replacement time less than 7.58 years? b) If the company wants to provide a warranty so that only 0.8% of the quartz time pieces will be replaced before the warranty expires, what is the time length of...
Company XYZ know that replacement times for the quartz time pieces it produces are normally distributed with a mean of 10.6 years and a standard deviation of 1.2 years. If the company wants to provide a warranty so that only 3.8% of the quartz time pieces will be replaced before the warranty expires, what is the time length of the warranty? warranty = years Enter your answer as a number accurate to 1 decimal place. Answers obtained using exact z-scores...
Company XYZ know that replacement times for the quartz time pieces it produces are normally distributed with a mean of 10.6 years and a standard deviation of 1.2 years. If the company wants to provide a warranty so that only 1.3% of the quartz time pieces will be replaced before the warranty expires, what is the time length of the warranty? warranty = years Enter your answer as a number accurate to 1 decimal place. Answers obtained using exact z-scores...
IN UUTUULLIS Company XYZ know that replacement times for the quartz time pieces it produces are normally distributed with a mean of 16.3 years and a standard deviation of 1.1 years. Find the probability that a randomly selected quartz time piece will have a replacement time less than 14 years? P(X< 14 years) = Enter your answer accurate to 4 decimal places. Answers obtained using exact 2-scores or 2-scores rounded to 3 decimal places are accepted If the company wants...
Company XYZ know that replacement times for the DVD players it produces are normally distributed with a mean of 6.7 years and a standard deviation of 1.6 years. Find the probability that a randomly selected DVD player will have a replacement time less than 2.2 years? P(X < 2.2 years) = Enter your answer accurate to 4 decimal places. Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted. If the company wants to provide a...
A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 93.4- cm and a standard deviation of 0.6-cm. Find the proportion of steel rods with lengths between 92 cm and 95.1 cm. Enter your answer as a number accurate to 4 decimal places. A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 155.6-cm and a standard deviation of 2-cm. A steel rod is...
A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 225.5-cm and a standard deviation of 2.2-cm. For shipment, 26 steel rods are bundled together. Find the probability that the average length of a randomly selected bundle of steel rods is greater than 224.2-cm.
A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 231.1-cm and a standard deviation of 2-cm. For shipment, 25 steel rods are bundled together. Find the probability that the average length of a randomly selected bundle of steel rods is between 230.5-cm and 230.6-cm.
A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 172.4-cm and a standard deviation of 1.4-cm. For shipment, 28 steel rods are bundled together. Find the probability that the average length of a randomly selected bundle of steel rods is less than 172.9-cm. P(M < 172.9-cm) =
A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 146.3-cm and a standard deviation of 0.5-cm. For shipment, 14 steel rods are bundled together. Find the probability that the average length of a randomly selected bundle of steel rods is between 146.2-cm and 146.6-cm. P(146.2-cm < M < 146.6-cm) =