here the linear regaression y^=1+2*X
or ,=-8.45+1.99EDUC
here slope is 2=1.99 and intercept 1=-8.45
error df=n-k=64-2=62
n=number of observation=64 and
k=number of regression coefficient=2
(a) (1-alpha)*100% confidence interval for slope 2=2 ±t(alpha/2, error df)*SE()
95% confidence interval =1.99±t(0.05/2, 62)*0.52=1.99±2.00*0.52=1.99±1.04=(0.95,3.03)
(b) (i)here null hypothesis H0:1=0 and
alternate hypothesis Ha: 10
(ii) test statistic t=(1)/SE(1) will followin t-distribution with error df=n-k
(iii) rejection region |t|>t(0.05,62)=2.00
or, rejection region t<-2.00 or t>2.00
(iv) calculated t=-8.45/7.39=-1.1434
(v) since calcuted t=-1.1434 does not belongs rejection region, so we accept the null hypothesis H0 and conclude that intercept is zero. in other worlds no education no wage.
the resulting model implies that the response function must be exactly zero when all the predictors are set to zero or at their reference levels. For an ordinary regression model this means that the mean of the response variable is zero.
2. Using data from 2013 on 64 black females, the estimated linear regression between WAGE (earnings...
Suppose you estimate the following model by OLS: wage = β0 + β1educ + β2exper + u wage : hourly age in dollars educ : years of education exper : years of experience You obtain the following fitted model using STATA, where standard errors are given in parenthesis wage [ = 3.5 + 0.9educ + 1.5exper (2.0) (0.7) (0.5) Number obs. : 523 R 2 = 0.45 For the following questions, make use to the relevant statistical tables. If you...
QUESTION 1 Consider the following OLS regression line (or sample regression function): wage =-2.10+ 0.50 educ (1), where wage is hourly wage, measured in dollars, and educ years of formal education. According to (1), a person with no education has a predicted hourly wage of [wagehat] dollars. (NOTE: Write your answer in number format, with 2 decimal places of precision level; do not write your answer as a fraction. Add a leading minus sign symbol, a leading zero and trailing...
) You have collected 14,925 observations from the Current Population Survey. There are 6,285 females in the sample, and 8,640 males. The females report a mean of average hourly earnings of $16.50 with a standard deviation of $9.06. The males have an average of $20.09 and a standard deviation of $10.85. The overall mean average hourly earnings is $18.58. a. Using the t-statistic for testing differences between two means (section 3.4 of your textbook), decide whether or not there is...
This question is based on Ch10, but we can solve it using our knowledge from Ch9. In Ch 8, we created confidence intervals to test whether the means differed in a statistically significant manner between two independent (unrelated) populations, like males and females. The sample point estimator in the confidence interval was the difference in the sample means between the 2 samples (xbar - ybar). We created a confidence interval of the form: (xbar-ybar) +/- (Zα/2)[standard error of (xbar-ybar)] We...
0.024 .00 d5 002 0.009 0.0033(.005) Constant 100 .324) a What is the estimated ctr to eacandeely o setively on education? Explain. (2ps) b. Based on the estimated models (1)nd (2) "d wth.5%-a" hdiol by mother's sth" married worker. (Aps) II. (15pts) You are given the following three estimated models, with all the variables described as in question II: Dependent variable: og(wage) (3) 2) educ 0.118 0.062 0.116 C0.024) (0.006) (0.024) 0.095s C0.029) meduc 0.094* C0.029) married 0.252 0.247* C0.071)...
A random sample of size 15 is obtained from a normal population yielding a sample standard deviation of 20. Test the null hypothesis that the unknown population variance is greater than or equal to 162 versus the alternative that the unknown population variance is less than 162 using a 5% level of significance a. Set up the null and alternative hypotheses, clearly defining any unknown parameters. Note the “=” value is always in the null hypothesis. b. Find a test...
asap i beg u IL. (15pts) You are given the following three estimated models, with all the variables described as in question II Dependent variable: log (wage) educ 0.056** 0.062* 0.049* 0.022) (0.006) (0.022) feduc 0.027 C0.027) 0.021 0.028) married 1.000 0.606 (0.518) (0.466) age 0.032 C0.114) (0.103) (0.116) 0.034 feduc. educ -0.001 (0.002) -0.0003 (0.002) married.age 0.037 0.025 C0.016) (0.014) 0.001 0.001 -0.00000 C0.002) C0.002) C0.002) agesq Constant 5.306**5.218* 5.090*** (1.923) C1.723) C1.932) observations 741 R2 741 0.151 741...
Where wage is in 1000's of dollars. Now suppose that your econometrics give you the to Wage = Bo + Bi Education + e that your econometrics give you the following results: Constant Education Coefficient 45.32 10.32 5 Standard Error 30.65 2.35 N=42 a. Estimate a 95% confidence interval for a 95% confidence interval for B.. Show your work carefully. What does this ence interval tell us about the relationship between education and wages? (2 marks) b. Test at the...
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