a)
for 30 min, = 5/2 = 2.5
P(X>= 2) = 1- P(X =0) - P(X = 1)
= 1 -e^(-2.5) (1 + 2.5)
=0.71270250481
b)
P( X = 0 in 1 hr | X = 0 in 30 min)
= P( X = 0 in 1 hr and X = 0 in 30 min) /P(X = 0 in 30 min)
= P( X = 0 in next 30 min and X = 0 in 30 min) / P( X = 0 in 30 min)
= P( X = 0 in next 30 min )
= e^(-2.5)
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