2. No of phone calls in 60 mins = 7.5
So no of phone calls in 1 min = 7.5/60 = 0.125
Let X= no of calls in a min
So, X~Poisson(0.125) distribution
PDF of X is given as: P(X=x) = e^-0.125*(0.125)^x/x!
a) We want, P(X=0) = e^-0.125 = 0.8825
b) P(X>3) = 1-P(X<=3) = 1- P(X=0) - P(X=1) - P(X=2) - P(X=3)
Putting these values of x in the PDF above and calculating the respective probabilies we get,
P(X>3) = 0.00001
3. a) Since n= 1024 is a very large sample we can use z score for the ci calculation. 95% CI for the mean u is given as:
Sample mean +-z*sample SD/√n
= 185.23 +-1.96*187.2/√1024
= (173.764, 196.696)
b) similarly 95% CI for Unicorn u is given as:
205.15 +- 1.96*160.3/√840
= (194.309, 215.991)
c) Since from the CI we can see that the mean time between failures is higher for Unicorn gateway, it seems more reliable than Zebra at the 5% significance level.
1. Consider the differential equation dy/dt = 0.2y(t) -2, y(0) = 40. (a) Showing your work,...