Question

An m = 7.57 g bullet is fired into a 259 g block that is initially at rest at the edge of a table of h = 1.00 m height as shown in the figure. The bullet remains in the block, and after the impact the block lands d = 1.85 m from the bottom of the table. How much time does it take the block to reach the ground once it flies off the edge of the table? Submit Answer Tries 0/12 What is the initial horizontal velocity of the block as it flies off the table? Submit Answer Tries 0/12 Determine the initial speed of the bullet. 1.44x102 m/s You are correct. 46520270 Previous Tries Your receipt no. is 155-6270 Previous tri

Answer 1

Use equation of kinematics in vertical and horizontal direction separately to find the required time and initial horizontal velocities of the block. Use conservation of momentum principle during collision to find the initial speed of the bullet as shown below

'x up is positive Y-ascis, for vertical motion from edge to ground, 1 ay = Voył + 2 hat² -) - h = oxt + 2/2 (-9-8 m/s2) t I put h= lm to get t = 0.452s { voy = 0 as Linitial velocity is horizontal at edge ? b) in horizontal direchion from edge to ground, Ax = Vox t d = Voxt => 1.85m = Vox (0.4525) - Vox = 4.10 m/s velocity of block at edge. c) from momentum conservation during collision, momentum before collision = moment um after collision => mv. = (M+ m) Vox Memor { Vose is. s vox is the speed of et (box after collision => [7.579) Vo = (2599+7.579) 4:10 m/8) - Vo = [144 m/s

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