Question

6.19 PLUS A jet of water (15.5°C) is discharging at a constant rate of 0.05 m/s from the upper tank. If the jet diameter at section 1 is 10 cm, what forces will be measured by scales A and B? Assume the empty tank weighs 1.4 kN, the cross-sectional area of the tank is 0.37 m², h = 0.3 m, and H = 2.7 m. Н T h B PROBLEM 6.19

Answer 1

Date Page Now, Q = 0.05 mee -32 d = o.im A 4 7.85x10 m V 6.36 m/sec Vnorizontal When it chits the lower tank, Venfical velocity (VW) = ? Vva of gxt here 8= H=2.7m v=v2x9.81x2.7 Vu = 7.27 m/sec Fw point • Force at force due to weight of wathy + Force clue to impulse of vertical (V) velocity of zet. + weight of empty tank. Fw= 0.37 x 0.3x9.81 kW 1.08 KN. Scanned with gamScanner

Page Fimpulse fave 1000 X 7.85X10 X (7027) ho'x (7:27) 2 looo 0.414 KN total force at A = 1:08+ 0.414+ 1.4 FA 2.894 KN (6) Force at B = F2= tory due to implllse of jet due to horizontal component a velocity. FR= pavy ² x (6.369 KN 1000 X 7.85*10 1000 JFB = 0.317 KN NH Scanned with CamScanner