Question

A doubly lonized (2) cesium atom passes with a velocity of 4.1X10 m/s through an Magnetic field of 1.3T. What magnetic field
0 0
Add a comment Improve this question Transcribed image text
Answer #1

Hii

To not get deflected Emagnetic = Felectric QUB =qE 4.18105x1.3=E E = 5.33*105 N/

Any query in solution then leave a comment

Please give me your valuable feedback

Thanks

Add a comment
Know the answer?
Add Answer to:
A doubly lonized (2) cesium atom passes with a velocity of 4.1X10 m/s through an Magnetic...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • An ion that is doubly ionized passes through the velocity selector and into the deflection chamber...

    An ion that is doubly ionized passes through the velocity selector and into the deflection chamber of a mass spectrometer, as shown below. In the velocity selector the electric field has a magnitude of 6958 W/m, and the magnitude of the magnetic field in both the velocity selector and the deflection chamber is 0.0855 T. If in the deflection chamber the ion is detected at a distance of 58.0 cm from its entry point, determine the following. O o +...

  • a) Doubly ionized Cesium ions are accelerated to 50 km/s in an ion rocket engine. What...

    a) Doubly ionized Cesium ions are accelerated to 50 km/s in an ion rocket engine. What accelerating voltage is needed assuming they start from rest? Each ionization removes one electronic charge. **(Mass is 2.225x10-25; Answer should be around 870V) b) A doubly ionized atom (charge = + 2e, where e = 1.602 X 10-19 C) falls in a field that lowers its potential energy by 2.7 X 10-16 J. Through what voltage does it fall? If the ion has mass...

  • A proton is traveling with a velocity of <420, -350, 780> m/s. As the proton passes...

    A proton is traveling with a velocity of <420, -350, 780> m/s. As the proton passes through the point <0.62, 0.27, -0.15> m, use Biot-Savart Law to determine the magnetic field caused by the proton at the location <-0.45, 0.13, 0.26> m.

  • An unknown charged particle passes without deflection through crossed electric and magnetic fields of strengths 187,500...

    An unknown charged particle passes without deflection through crossed electric and magnetic fields of strengths 187,500 V/m and 0.1250 T, respectively. The particle passes out of the electric field, but the magnetic field continues, and the particle makes a semicircle of diameter 25.05 cm. What is the particle's charge-to-mass ratio? Can you identify the particle? can't identify proton electron neutron

  • The magnetic flux that passes through one turn of a 30-turn coil of wire changes to...

    The magnetic flux that passes through one turn of a 30-turn coil of wire changes to 2.0 Wb from 11.0 Wb in a time of 0.028 s. The average induced current in the coil is 155 A. What is the resistance of the wire? (10 points) 1) 2) A proto n in a particle accelerator has a speed of 5.0 X 10 m/s. The proton encounters a magnetic field whose magnitude is 0.40 T a) Find the magnitude of the...

  • QUESTION 2 An electron with velocity v - (12 m/s) i moves through a magnetic field...

    QUESTION 2 An electron with velocity v - (12 m/s) i moves through a magnetic field (4.0T), and denote unit vectors pointing along the x, , and axes, respectively.) Find the direction of the force on the electron b) c-k d.-1

  • с Homework – Unanswered A doubly charged helium atom whose mass is 6.6x10^-27 kg is accelerated...

    с Homework – Unanswered A doubly charged helium atom whose mass is 6.6x10^-27 kg is accelerated by a voltage V=2700.0 V and enters the area of magnetic field perpendicular to its velocity B=0.20 T. What is its period of revolution? Numeric Answer: Unanswered • 5 attempts left Submit D Homework. Unanswered An electron enters uniform magnetic field B=0.30 T at angle 45 degrees to B with speed v=1.5*10^6 m/s. Find pitch (distance between loops) of the electron's helical path. Numeric...

  • answer both QUESTION 1 An electron with velocity - (12 m/s) i moves through a magnetic...

    answer both QUESTION 1 An electron with velocity - (12 m/s) i moves through a magnetic field B - (4.0T) k. (i), and k denote unit vectors pointing along the x, y, and axes, respectively.) Find the magnitude of the force on the electron 08.77* 10-18N b.3.3 * 10-19 C. 48 N d. 6.0 N QUESTION 2 An electron with velocity - (12 m/s) i moves through a magnetic field B - (4.0T) k. (.), and k denote unit vectors...

  • An alpha particle travels at a velocity of magnitude 460 m/s through a uniform magnetic field...

    An alpha particle travels at a velocity of magnitude 460 m/s through a uniform magnetic field of magnitude 0.056 T. (An alpha particle has a charge of charge of +3.2 × 10-19 C and a mass 6.6 × 10-27 kg) The angle between the particle's direction of motion and the magnetic field is 61°. What is the magnitude of (a) the force acting on the particle due to the field, and (b) the acceleration of the particle due to this...

  • An alpha particle travels at a velocity of magnitude 580 m/s through a uniform magnetic field...

    An alpha particle travels at a velocity of magnitude 580 m/s through a uniform magnetic field of magnitude 0.046 T. (An alpha particle has a charge of charge of +3.2 × 10-19 C and a mass 6.6 × 10-27 kg) The angle between the particle's direction of motion and the magnetic field is 56°. What is the magnitude of (a) the force acting on the particle due to the field, and (b) the acceleration of the particle due to this...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT