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webwork / math131_s20 /homework 4/7 Homework 4: Problem 7 Previous Problem Problem List Next Problem (6 points) Find the absolute maximum and minimum values of f(x) = -(x + x) i over the interval(-2,3]. absolute maximum is absolute minimum is and it occurs at x = and it occurs at x = Notes: If there is more than one x value, enter as a comma separated list. Note: You can earn partial credit on this problem. Preview My Answers Submit Answers You have attempted this problem o times. You have 3 attempts remaining. Email WebWork TA

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solution FIM) = -C 2² + 2) 2 -( ²+2) T (-2,3] J for knowing Take derive tive both side Critical points then deco etag (- (n = n34) = -3(nn)" (2011) WIN WIN ant) 12²+ n) put f'(o)=0 - 2 (204)) =0 (2²+ n) est n = 1 n = 0 and at n= -1 f'(a) becomes o then critical nimmbers are -=-1,0,-1 ne (-2,37 How Again differenciate with respect son 2 a f(n) - 2d an 3d quotient 2 .6410) 2432 2 (2011) Susing (22+2) / rule cm tm's.2 (2011) § (m)43 20m2x)'s - (min)%3 - )'s)

at na - 1 / 2 f(n) is the then fm) is minimum at no-1 ROEPG f(-12) 2 - 2 at n=-1 l ''(s) is tve fin) = 0 and at no Fin) = 0 le, Maximum values ne [23] How check at n = 3 f(n) = -5-24-14 then this is Global Absolute ) Minima Crlobal (Absolute) maxima at (mifin) = (-1,0) ( f(n) = (0,0) Local Minima = (s, for n E [2,3] (-0.5, -0.396) Local maxima ) [n, f(n)) (-1,0) and (oo) ne (-2, 3] Aue