Question

Write down the Canonical SOP expression for :

_{F = (abc'+a'c'+b'c)'}

Answer 1

$\small \color{blue}Answer:\;\;$

F = (abc'+a'c'+b'c)'

= (abc')' (a'c')' (b'c)'

= (a'+b'+c) (a+c) (b+c')

we can write this in POS form as π(0, 1, 2, 5, 6)

so, we can write the SOP form as Σ(3, 4, 7)

hence canonical SOP form is

F = a'bc + ab'c' + abc

Answer:

F = a'bc + ab'c' + abc