Question

HIS LUGDUI. TOP Find the area of the specified region. Shared by the circles r = 2 and r = 4 sin OA. ? / (48-313) OB. 21 oc. ? //22 + 3/3) Click to select your answer Type here to search

Answer 1

if any doubt pls comment

Ant we have to find the Shaded region sherred by the two circle r=2 and s=4 sine. If we draw the same picture by intersecting the circles a same radious going through the centre of each other. he area of a circle sector with radious 2 and amplitude 6o is not x 60 78² if the area of the shaded region (beside) is in since here 8=2 so the area is 57.22 - 27. and the orren of an equilarteras triangle with side length 2 iss 3. u = rz, hence the area of the circle Seyment by the differene of this two objects is 27 - 3. ý the area of the shaded. region (beside). so the area of the shared regim - area of the two equilaterad triangle + ax (27 – 3) = 23+ 4*(??-13) - 3 - 2r3 (41 - 313) 2020