Question

Using simple, college level c++ programming

Design a class called NumDays. The class’s purpose is to store a value that represents a number of work hours and convert it to a number of days. For example, 8 hours would be converted to 1 day, 12 hours would be converted to 1.5 days, and 18 hours would be converted to 2.25 days. The class should have a constructor that accepts a number of hours, as well as member functions for storing and retrieving the hours and days. The class should also have the following overloaded operators:

+ Addition operator. When two NumDays objects are added together, the overloaded + operator should return the sum of the two objects’ hours members.

- Subtraction operator. When one NumDays object is subtracted from another, the overloaded operator should return the difference of the two objects’hours members.

++ Prefix and postfix increment operators. These operators should increment the number of hours stored in the object. When incremented, the number of days should be automatically recalculated.

-- Prefix and postfix decrement operators. These operators should decrement the number of hours stored in the object. When decremented, the number of days should be automatically recalculated.

Answer 1

solution:

#include <iostream>

#include <string>

using namespace std;

class NumDays

{

private :

int days;

int hrs;

public:

NumDays(int hrs)

{

this->hrs=hrs;

}

int getHrs()

{

return hrs;

}

void setHrs(int hrs)

{

this->hrs=hrs;

}

float getDays()

{

return hrs/8.0;

}

NumDays operator+(NumDays n)

{

NumDays nd(hrs+n.getHrs());

return nd;

}

NumDays operator-(NumDays n)

{

NumDays nd(hrs-n.getHrs());

return nd;

}

// Post-increment Operator

NumDays operator++()

{

hrs++;

return *this;

}

// Post-decrement Operator

NumDays operator--()

{

hrs--;

return *this;

}

// Pre-increment Operator

NumDays operator++(int)

{

NumDays old(*this);

++(*this);

return old;

}

// Pre-decrement Operator

NumDays operator--(int)

{

NumDays old(*this);

--(*this);

return old;

}

};

int main ()

{

NumDays n1(8),n2(12),n3(18);

cout<<"After converting "<<n1.getHrs()<<" hrs to days is "<<n1.getDays()<<endl;

cout<<"After converting "<<n2.getHrs()<<" hrs to days is "<<n2.getDays()<<endl;

cout<<"After converting "<<n3.getHrs()<<" hrs to days is "<<n3.getDays()<<endl;

cout<<"No of Hrs in n1 Before PostIncrement "<<n1.getHrs()<<endl;

n1++;

cout<<"No of Hrs in n1 After PostIncrement "<<n1.getHrs()<<endl;

cout<<"No of Hrs in n2 Before PostDecrement "<<n2.getHrs()<<endl;

n2--;

cout<<"No of Hrs in n2 After PostDecrement "<<n2.getHrs()<<endl;

cout<<"No of Hrs in n2 Before PreIncrement "<<n2.getHrs()<<endl;

++n2;

cout<<"No of Hrs in n2 After PreIncrement "<<n2.getHrs()<<endl;

cout<<"No of Hrs in n3 Before PreDecrement "<<n3.getHrs()<<endl;

--n3;

cout<<"No of Hrs in n3 After PreDecrement "<<n3.getHrs()<<endl;

NumDays n4=n1+n2;

cout<<" No of Hrs after adding n1 and n2 is "<<n4.getHrs()<<endl;

cout<<" No of Days in n4 is "<<n4.getDays()<<endl;

NumDays n5=n3-n1;

cout<<" No of Hrs after subtracting n1 from n3 is "<<n5.getHrs()<<endl;

cout<<" No of Days in n5 is "<<n5.getDays()<<endl;

return 0;

}

__________________

Output:

C:\Program Files (x86)\Dev-Cpp\MinGW64\bin\ClassNumDaysPreincrementPostIncrementOperato.. After converting 8 hrs to days is 1 After converting 12 hrs to days is 1.5 After converting 18 hrs to days is 2.25 No of Hrs in n1 Before PostIncrement 8 No of Hrs in n1 After PostIncrement 9 No of Hrs in n2 Before Post Decrement 12 No of Hrs in n2 After Post Decrement 11 No of Hrs in n2 Before PreIncrement 11 No of Hrs in n2 After PreIncrement 12 No of Hrs in n3 Before Pre Decrement 18 No of Hrs in n3 After PreDecrement 17 No of Hrs after adding ni and n2 is 21 No of Days in n4 is 2.625 No of Hrs after subtracting ni from n3 is 8 No of Days in n5 is 1 Process exited after 0.03474 seconds with return value o Press any key to continue . . .

please give me thumb up