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Microfracture knee surgery has a 79% chance of success of patients with degenerative knees. The surgery is performed on 13 pa
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Answer #1

p=probability of success of surgery = 0.79

n= number of patients taken = 13

X= number of patients having a successful surgery

Thus X~Binomial(n=13, p=0.79) [ since there is n number of trials and probability of success equal to p)

13 0.79(0.21)13- P(X x)           x=0,1,,,,,,,,,,13

a)

P(surgery is successful on all patients) = P(X=13)

130.79 (0.21)1-18 P(X 13) 0.04668229

b)

P(surgery is successful on atmost 10 patients) = P(X<=10) = 1-P(X>10) =1-P(X>=11)

13 P(X 21) -Σ() 0.79(0.21) 13-r r-11 = 0.4652970

So,

P(X10 1 - P(X> 10)1 P(X 11) 1 0.4652970 = 0.5347030

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