The isotope 143Pr undergoes beta decay with a half-life of 13.57 days. What fraction of 143Pr has decayed after 11.6 days?
Radio active edecay is always first order reaction.
Lambda = 0.693 / 13.57days = 0.0512 days-1
Lambda = (2.303 / t ) Log (a / a-x)
0.0512 = (2.303 / 11.6 ) Log(1/1-x)
1/(1-x) = 1.81
1-x = 0.552
x = 0.448
So fraction of decay after 11.6 hours = 44.8 %
The isotope 143Pr undergoes beta decay with a half-life of 13.57 days. What fraction of 143Pr...
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