Question

for the acceleration of gravity) wymbol stated above along with the following as necessary (a) At the instant the rod is horizontal find its angular speed. (Use any variat for the D) At the instant the rod is horizontal, find the magnitude of its angular acceleration. (Use any variable or symbol stated above along with the following as necessary acceleration of gravity) (c) At the instant the rod is horizontal, find the x and y components of the acceleration of its center of mass. (Use any variable or symbol stated above along with the following as necessary for the acceleration of gravity.) (0) At the instant the rod is horizontal, find the components of the reaction force at the pivot. (Use any variable or symbol stated above along with the following as necessary: 9 for the acceleration of gravity)

Answer 1

We know that center of mass lie in the middle for a uniform som CM 3- i PUMA À wing SE-952- 2 about point A moment of inertin of rod se me By work energy theorem - rotation of Kinetic energy of Dorike done by gravity = no rood om 7 * me qiw ? 3 mg L = 10² (s: me) = mgi - ml cd? = Cð? - 3 @> (W = right cangular speed when it is) o horizontal © angular acceleration @ - Torque e = 10 Torque about point A a = mg x 1 / 2 = ml x x 1a - angular aceleration © There is no motion of rod in horizontal direction Hence t o only centripital acceleration in horizontal direction ax = W²1/2 = 39 x 1 = 39
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in vertical direction is acting only gravital accderation 2L Re is responsible for horizontal (centripital acceleration) Roxe = med u he = m 39 x 2 Re esempio in vertical direction acceleration acceleration is only g it means rod is falling freely under only gravity hence