Question

Prove that sinhx =( e^x - e^-x/ 2), coshx = (ex+e^-x/2) is equal to: sinh x=...

Prove that

sinhx =( e^x - e^-x/ 2), coshx = (ex+e^-x/2)

is equal to: sinh x= x+x^3/3! + x^5/5! ... and cosh x= 1+ x^2/2! +x^4/4! ..

USE THIS EQUATION: e^x = sum x^n/ n! = 1+x+(x^2/2!) +(x^3/3! )

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