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Question 1 (based on the example to the example we worked in class) (30 points) Consider an Air Standard Otto Cycle in which

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SOLUTION: The (Wola I (HR) Vy v V2 = V3 =VC -VetVc Given -2.8x10 (HA) Heat added at constant volume. (FOR) V → Heat rejected-10.09 O.ossxo-3 8=8o le compression Ratio r=re = = 0.555x10 3 -10.09 0.05sx 103 (As it is offo cycle, so, 8=re le compre & EFor Process 2 3 PV=MRT I = MR =C 175627 8079 x 43.93 = P2 300 P = 1104.67 kPa T 13 P2 = 283.43 x 1104-67 = 7717.4 KB To 756.2Now, = 1 - (2095.84 – 300) - 0.80 @ 60% (5283-43-756.2) thermal is 60% ont Awnantowy (WoD) Net Awis + W278 + AW 3-4 tau =0 ;

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