Question

A relativistic train of proper length 249 m approaches a tunnel of the same proper length, at a relative speed of 0.922c. A p

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Answer #1

a) tunnel length as seen by train is conctracted

L=L_0\sqrt{1-\frac{v^2}{c^2}}

L0 is proper length

so we get

L=96.41m

b) as view by the tarin length of tunnel is shorter than train so front of train passes far end of tunnel so FF occurs first

c) time diference is

\Delta t=\frac{L_0/v}{\sqrt{1-\frac{v^2}{c^2}}}

so we get

\Delta t= 6.62 \times 10^{-6}s= 6.62 \mu s

d)now because FF event occur first so bomb will explode

e)so due to relative speed of train length will contract and

L=L_0\sqrt{1-\frac{v^2}{c^2}}

L= 96.41 m

f) now the RN event occur first

g) so time between those events is

\Delta t=\frac{L}{v}=3.48\times 10^{-7}s= 0.348\mu s

h)now because as from tunnel view RN event occur first so bomb will not explode

There is parodox in both events as seen by tunnel and train view but it is actually not possible to decide either it explode or not because above argument is made over view by either train or tunnel but physically both of there length is same so both event occur simultaneously

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