Question

You illuminate a slit of width 0.0505 mm with light of wavelength 737 nm and observe the resulting diffraction pattern on a screen that is situated 2.47 m from the slit. What is the width, in centimeters, of the pattern's central maximum? Number Incorrect This is the distance from the maximum of the central peak to the first 3.6 cmminimum (dark spot). The width of the central peak is the distance between the two minima on either side of the central peak

The answer in the "number" box is incorrect. The sentence in red is a hint/explanation as why it is incorrect. Please find the correct answer to the nearest hundredth

Answer 1

Width of central maxima = 2 pi D/d = 2 times 737 times 10^-9 times 2.47/0.0505 times 10^-3 = 720943653 times 10^-6 m = 72.094 times 10^-3 m = 7.2 cm Width of central maxima = 7.2 cm