Question

Brief Exercise 26-11 Kanye Company is evaluating the purchase of a rebuilt spot- welding machine to be used in the manufacture of a new product. The machine will cost $176,000, has an estimated useful life of 7 years, a salvage value of zero, and will increase net annual cash flows by $38,564 What is its approximate internal rate of return? (Round answer to O decimal place, e.g. 125.) Internal rate of return

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Answer #1

Answer

  • Answer = 12%

  • Internal Rate of Return [or IRR] is that interest rate where the present values of future annual cash flows when discounted becomes EQUAL to the Initial Investment cost.
  • This means that:

--Present Value of annual cash flows = Initial Cost

OR

--Net Present Value = $ 0, because NPV = Present values of annual cash flows – Initial Cost.

  • Present value of annual Cash flows = Annual Cash Flows x Present value of annuity of $ 1 at IRR
  • Hence, NPV = (Annual Cash Flows x Present value of annuity of $ 1 at IRR) – Initial Cost

$ 0 = ($ 38,564 x Present value of annuity of $ 1 at IRR) - $ 176,000

0 = (38564 x Present value of annuity of $ 1 at IRR) – 176000

0+176000 = 38564 x Present value of annuity of $ 1 at IRR

176000/38564 = Present value of annuity of $ 1 at IRR

Present value of annuity of $ 1 at IRR = 4.56384….

  • Now you have to look into factor table to see which interest rate’s annuity value at 7th period equals 4.56384….

8%

9%

10%

11%

12% = ANSWER

13%

14%

1

0.925925926

0.917431193

0.909090909

0.900900901

0.892857143

0.884955752

0.877192982

2

0.85733882

0.841679993

0.826446281

0.811622433

0.797193878

0.783146683

0.769467528

3

0.793832241

0.77218348

0.751314801

0.731191381

0.711780248

0.693050162

0.674971516

4

0.735029853

0.708425211

0.683013455

0.658730974

0.635518078

0.613318728

0.592080277

5

0.680583197

0.649931386

0.620921323

0.593451328

0.567426856

0.542759936

0.519368664

6

0.630169627

0.596267327

0.56447393

0.534640836

0.506631121

0.480318527

0.455586548

7

0.583490395

0.547034245

0.513158118

0.481658411

0.452349215

0.425060644

0.399637323

5.20637

5.03295

4.86842

4.71220

4.5638 = matches the value

4.42261

4.28830

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