= 0.98
/2 =
0.98/2
/2 =
0.49
Look for this value in the area under normal curve table.
The nearest value is 0.4901
So the Z value is 2.33.
Z = 2.33
gnment Chapter 08, Section 8.2, Problem 010 Find z for a 98% confidence level. Round your...
gnment Chapter 07, Section 7.6, Problem 062a For a population, N = 20,000 and p = 0.17. Find the z value for p = 0.26 for n = 80. Round your answer to two decimal places. the tolerance is +/-5%
Chapter 08, Section 8.2, Problem 011 For a data set obtained from a sample, n a. What is the point estimate of H? 81 and x = 45.55. It is known that ? = 4.2. The point estimate is b. Make a 95% confidence interval for Round your answers to two decimal places. c. What is the margin of error of estimate for part b? Round your answer to three decimal places. Click if you would like to Show Work...
Chapter 5, Section 2, Exercise 034 Find the z' values based on a standard normal distribution for each of the following. (a) An 80% confidence interval for a proportion. Round your answer to three decimal places. z* = + the absolute tolerance is +/-0.01 (b) An 82% confidence interval for a slope. Round your answer to three decimal places. +2 the absolute tolerance is +/-0.01 (c) A 92% confidence interval for a standard deviation. Round your answer to three decimal...
Mechanics of Fluids
GNMENT RESOURCES Chapter 08, Problem 122 Water flows through the orifice meter shown in the figure below at a rate of 0.10 fs. If d-0.12 ft, determine the value of h. gnment 9- Chapter 0L1 apter 08.Practice oblem 8.23 uhisten) apter 08 Problem 3GO Tutoria) 4.9 the tolerance is +/-2% w Score w Results by Study
Chapter 08, Section 8.2, Intelligent Tutoring Problem 011 For a data set obtained from a sample of size n-81 with x-47.75, it is known that ?-5.6. (a) what is the point estimate of ?? (b) Find z score corresponding to a 95% confidence level, zo/2. Recall that (1-a)100%-95%. (c) Construct a 95% confidence interval for ?. (d) What is the margin of error in part (c)? Recall the following definitions from section 8.2-3 of the text. The confidence level is...
*Chapter 6, Section 1-CI, Exercise 011 Use the normal distribution to find a confidence interval for a proportion p given the relevant sample results. Give the best point estimate for p, the margin of error, and the confidence interval. Assume the results come from a random sample. A 99% confidence interval for p given that p = 0.36 and n = 500. Round your answer for the best point estimate to two decimal places, and your answers for the margin...
Chapter 5, Section 1, Exercise 013 Find the p-value based on a standard normal distribution for each of the following standardized test statistics (a) Z = 0.89 for a right tail test for a difference in two proportions Round your answer to two decimal places p-value0.20 the absolute tolerance is +/-0.01 (b) Z-_2.39 for a left tail test for a difference in two means Round your answer to three decimal places. p-value- the absolute tolerance is +/-0.001 (c) = 2.18...
Find the critical value z/α2 needed to construct a confidence interval with level 99.7% .Round the answer to two decimal places. The critical value for the 99.7%confidence level is __?
confidence level and sample data to find confidence interval
for estimating a population round your answer to the same number of
decimal places as a sample
Question 2 2 pts Assume that a sample is used to estimate a population proportion p. Find the margin of error E that corresponds to the given statistics and confidence level. Round the margin of error to four decimal places. 90% confidence; n 390, x-146
Chapter 03, Problem 010 (Video Solution) In order to buy a car, you borrow $32,500 from a friend at 14%/year compounded monthly for 4 years. You plan to repay the loan with 48 equal monthly payments ▼ Part a Your answer is correct. 888.23per month How much are the monthly payments? Round entry to two decimal places. The tolerance is ±1. Click here to access the TVM Factor Table Calculator. LINK TO TEXT LINK TO VIDEO Attempts: 1 of 2...