I2(g)+Cl2(g)⇌2ICl(g)K=6.91×103 at 460 K Calculate ΔrG for the reaction at 460 K under each of the following conditions:

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Question

I2(g)+Cl2(g)⇌2ICl(g)K=6.91×103 at 460 K Calculate ΔrG for the reaction at 460 K under each of the following conditions:

a) standard conditons

b) at equilibrium

c) $P_{I_{2}}$ = 0.325 $b a r$
$P_{C l_{2}}$ = 0.285 $b a r$
$P_{I C l}$ = 2.55 $b a r$

Chemisry thermodynamics Gibbs-Energy university Equilibrium

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Answer 1

Answer #1

The 3 given reaction Iz (g) + Cl₂ (9) 2 Bc I (g) K = 6.91xlo 6.325 bar 0.285 bar 2.55 bar (4) At standard condition AG = - RT So ∆G_rxn = -17.55 KJ/mol

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Answer 2

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I2(g)+Cl2(g)⇌2ICl(g)K=6.91×103 at 460 K Calculate ΔrG for the reaction at 460 K under each of the following conditions:

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I2(g)+Cl2(g)⇌2ICl(g)K=6.91×103 at 460 K Calculate ΔrG for the reaction at 460 K under each of the following conditions:

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Consider this reaction: I2(g)+Cl2(g)⇌2ICl(g) K=6.91×103 at 460 K Calculate ΔrG for the reaction at 460 K...

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I2(g)+Cl2(g)⇌2ICl(g)K=6.91×103 at 460 K Calculate ΔrG for the reaction at 460 K under each of the following conditions:

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I2(g)+Cl2(g)⇌2ICl(g)K=6.91×103 at 460 K Calculate ΔrG for the reaction at 460 K under each of the following conditions: