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sherlock holmes Question 2. A wealthy philanthropist well-known in London's high society was murdered in his...

sherlock holmes Question 2. A wealthy philanthropist well-known in London's high society was murdered in his home. Sherlock Holmes finds a blood-stained golf club in a dumpster 2 blocks from the philanthropist's home. The blood test measurement on the golf club blood has value -14.2. Use the least squares prediction equation to estimate the age of the person whose blood is on the golf club (use 2 decimal places).

Question 3. Help Holmes solve this murder mystery by calculating a 99% prediction interval for the age of the person whose blood is on the golf club (use 2 decimal places). lower bound of prediction interval_______________ upper bound of prediction interval_______________ Blood Test Measure Age in Years

http://www.webassign.net/userimages/blood%20test%20human%20age.xls?db=v4net&id=331902

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Answer #1

We Fit the simple linear regression model using Excel

SUMMARY OUTPUT
Regression Statistics
Multiple R 0.928555
R Square 0.862215
Adjusted R Square 0.861783
Standard Error 8.441812
Observations 321
ANOVA
df SS MS F Significance F
Regression 1 142257.1 142257.1 1996.193 2.4E-139
Residual 319 22733.28 71.26419
Total 320 164990.3
Coefficients Standard Error t Stat P-value Lower 95% Upper 95% Lower 95.0% Upper 95.0%
Intercept -28.3431 1.625332 -17.4384 2.67E-48 -31.5409 -25.1454 -31.5409 -25.1454
Blood Test Measure -6.46363 0.144669 -44.6788 2.4E-139 -6.74825 -6.179 -6.74825 -6.179

Here the model fitting good(as Pvalue <0.05).

Both coefficent are also significant( P Value <0.05)

So,

Model is

Age=-28.3431-6.46363*Test Value

Q2:

if Test Value=-14.2

Age=-28.3431-6.46363*-14.2=63.44045

Q3:

n 321
df 319
mean(x) -10.7524
x0 -14.2
Intercept -28.3431
Slope -6.46363
y_hat 63.4404
Sres 8.441812
SSx 3405.031
se 0.686126
t_Crit 2.591329
Lower 61.66242
Upper 65.21838

Formula Sheet:

Blood Test Measure Age in Years
-15.49 78.2 n =+COUNT(B2:B322)
-11.04 51.3 df =+E2-2
-13.62 70.1 mean(x) =AVERAGE(A2:A322)
-7.79 7.6 x0 =+-14.2
-14.84 77.9 Intercept =+INTERCEPT(B2:B322,A2:A322)
-8.3 20.1 Slope =+SLOPE(B2:B322,A2:A322)
-9.83 24.4 y_hat =+E6+E7*E5
-15.12 65.7 Sres =+STEYX(B2:B322,A2:A322)
-13.31 55 SSx =+DEVSQ(A2:A322)
-14.66 72.5 se =+E9*SQRT(1/E2+(E5-E4)^2/E10)
-15.77 63 t_Crit =+TINV(0.01,E3)
-15 64.7 Lower =+E8-E11*E12
-10.45 38.7 Upper =+E8+E12*E11
-7.68 26.1
-15.93 76.2
lower bound of prediction interval___61.66____________ upper bound of prediction interval_______65.22________ Blood Test Measure

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