An electron has a de Broglie wavelength λ = 5.1×10−10 m . h=6.626×10−34J⋅s, e=1.602×10−19C, me=9.109×10−31kg. Part A What is its momentum? (two significant figures with units) Part B What is its speed? (two significant figures with units) Part C What voltage was needed to accelerate it from rest to this speed? (two significant figures with units)
An electron has a de Broglie wavelength λ = 5.1×10−10 m . h=6.626×10−34J⋅s, e=1.602×10−19C, me=9.109×10−31kg. Part...
An electron has a de Broglie wavelength λ = 5.7×10−10 m . h=6.626×10−34J⋅s, e=1.602×10−19C, me=9.109×10−31kg. What is its momentum? What is its speed? What voltage was needed to accelerate it from rest to this speed?
Find the de Broglie wavelength λ for an electron moving at a speed of 1.00×106m/s. (Note that this speed is low enough that the classical momentum formula p=mv is still valid.) Recall that the mass of an electron is me=9.11×10−31kg, and Planck's constant is h=6.626×10−34J⋅s.
An electron has a de Broglie wavelength λ = 4.1×10−10 m . a) What is its momentum? b) What is its speed? c) What voltage was needed to accelerate it to this speed?
An electron has a de Broglie wavelength λ = 3.9 10-10 m. (a) What is its momentum? _____ kg·m/s (b) What is its speed? _____ m/s (c) Through what voltage difference does it need to be accelerated to reach this speed? _____ V (d) What's the speed of a 50 kg person having a de Broglie wavelength of λ = 4.4e-38 m? _____ m/s
An electron has a de Broglie wavelength ? = 4.3 10-10 m. (a) What is its momentum? kg·m/s (b) What is its speed? m/s (c) What voltage was needed to accelerate it to this speed?
Part A
What is the speed of an electron with a de Broglie wavelength of
0.17nm ?
Express your answer using two significant figures.
Part B
What is the speed of a proton with a de Broglie wavelength of
0.17nm ?
Express your answer using two significant figures.
Learning Goal: To understand de Broglie waves and the calculation of wave properties. In 1924, Louis de Broglie postulated that particles such as electrons and protons might exhibit wavelike properties. His thinking was guided by the notion that light has both wave and particle characteristics, so he postulated that particles such as electrons and protons would obey the same wavelength-momentum relation as that obeyed by light: λ=h/p, where λ is the wavelength, p the momentum, and h Planck's constant. Part...
An electron has de Broglie wavelength 2.81x10-10 m. Part A Determine the magnitude of the electron's momentum pe. Express your answer in kilogram meters per second to three significant figures. ► View Available Hint(s) IVO AKO o ? Pe = kg. m/s
Calculate the de Broglie wavelength of (a) a 1.15 keV electron (mass = 9.109 x 10-31 kg), (b) a 1.15 keV photon, and (c) a 1.15 keV neutron (mass = 1.675 x 10-27 kg). (a) Number 10.0362 Units nm (b) Number 10.762 Units nm (c) Numbe76.44e-4 units Inm
Through what potential difference should you accelerate an electron from rest so its de Broglie wavelength will be the size of a hydrogen atom, about 0.1 nm? Give your answer to two significant figures