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Problem 2:
(a) The value on bigendian is FF
Explanation: In bigendian we look at the highest
significant bit.
0x112233445566778899AABBCCDDEEFF
(b) The on littleendian is 11
Explanation: In bigendian we look at the least significant
bit. 0x112233445566778899AABBCCDDEEFF
(ii) f = g - A[C[16) + B[321) (iii) A[i] 4B[8i-811 + 4C[32i+321 Problem 2. Consider...