Question

pleease solve them for me now pleeeaaase

some of them have multiple answers

x²-v If L= lim (x, y) + (0,0) X x+v then along y = mx, so limit exist L 1-mo 1+ m2 along path x = my, and limit does not exist L = m2 -1 0 m +1 along the path X = my and limit does not exist L m-1 0 m + 1 along y=mx? and limit does not exist L 1.-mo 1 + m

Answer 1

L = lim x²_y ("")+10,0) x²+y Take y=ma =- L= X2- mu x²+ mn lim 20 = lim x-m. Ktm 240 c -1 lim yo LE Itm along x = my m²y-! lim m2y²_y yho m2ytl h?у? +9 alomo y = mal lim 42 ma2 1-m 2²+muz for different value limit is different. o limit does not exist last option option is correct +), L= 2-10 m q ce # x²y + az + z²=4 co こと 217 + 7+maz +2727 ax ox -127972) dz (X+27) ax az ax Ophon (2 (2x4 + ) x+2Z correct .