A mixture of 9.22 moles of A, 10.11 moles of B, and 27.83 moles of C...
A mixture of 9.22 moles of A, 10.11 moles of B, and 27.83 moles of C is placed in a one-liter container at a certain temperature. The reaction is allowed to reach equilibrium. At equilibrium the number of moles of B is 18.32. Calculate the equilibrium constant for the reaction: 
A (g) + 2 B (g)<-> 3 C (g)
Answer is supposed to be .0832. How? Also, how do you determine which way the reaction is going? Thanks
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A mixture of 9.22 moles of A, 10.11 moles of B, and 27.83 moles
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