1. A ray hits an object at 15° from the vertical. If
the material has index of refraction 1.5, what is the refraction
angle?
2. If a ray is incident on a block of material at 15° from the
vertical, and is refracted to 8° from the vertical, what is the
index of refraction?
3. A ray of light crosses from a flint glass slab at 20° from the
normal into air. At what angle does it emerge?
4. A ray of light passes through a prism, making the minimum angle
of deviation. The rays enter and emerge at 7° from the normal to
the surface. What is the index of refraction of the material, if
the prism angle is 50°?
From Snell's law or law of refraction
na sin theta = nb sin theta b
where na is refractive index of medium a and
nb is refractive index of medium b
theta is angle of incidece and theta b is angle of refraction
1. theta a = 15 degrees , theta b = ?
na = 1 air , nb= 1.5
na *sin theta = nb *sin theta b
1 sin 15 = 1.5 sin theta b
theta b = 9.94 degrees
so the angle of refraction is theta b = 9.94 degrees
2. na = 1 , nb = ? , theta a = 15 degrees , theta b = 8 degrees
susbtituting in the formula
na *sin theta = nb *sin theta b
1 sin 15 = nb sin theta 8
nb = 1.86
3.
theta a = 20 degrees , na = 1.655 , nb = 1
susbtituting in the formula
na *sin theta = nb *sin theta b
1.655*sin20 = 1 sin thetab
theta b = 34.47 degrees
4.
A = 50 degrees , Dm = 7 degrees
from the formula of the refractiveindex of prism with angle of prism A and angle of minimum deviation Dm
n = Sin((A+Dm)/2)/ sin (A/2)
n = sin((50+7)/2)/sin(50/2)
n = sin (28.5)/sin25
n = 1.13
so the refractive index of the given prism is n = 1.13
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