A uniform, 24.5 kg beam of length 2.90 m is hanging horizontally as shown in the diagram below. It is pinned to a vertical wall at point B and supported by a uniform 15.9 kg diagonal brace that is pinned at point C on the beam and at point A on the wall. [Use g = 9.80 m/s2.]
There is a load W, with a weight of 211 N, hanging at the end of
the horizontal beam. The distance BC is 2.17 m, and the distance AB
is 1.63 m. (The distance BD is 2.90 m.)
(a) Draw a free-body diagram for the horizontal beam, showing only
forces that act on the beam, using Cx and Cy
for the components of the force acting at point C. Use torques
about an axis at point B to solve for the vertical component of the
force on the horizontal beam at joint C: (Use "+"
if the force component is up, "-" if it is down.)
Cy =
(b) Draw a free-body diagram for the brace, including only
forces that act on the brace. Use torques about the point A to
solve for the horizontal component of the force on the
diagonal brace at joint C: (Use "+" if the force component
is right, "-" if it is left.)
Cx =
(c) Find the horizontal and vertical components of the force
on the horizontal beam at the joint B. Use "+" for
forces up or to the right, "-" for forces down or to the
left.
Bx =
By =
(d) Find the horizontal and vertical components of the force
on the diagonal brace at the joint A. Use "+" for
forces up or to the right, "-" for forces down or to the
left.
Ax =
Ay =
A uniform, 24.5 kg beam of length 2.90 m is hanging horizontally as shown in the...
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