Question

A uniform, 24.5 kg beam of length 2.90 m is hanging horizontally as shown in the...

A uniform, 24.5 kg beam of length 2.90 m is hanging horizontally as shown in the diagram below. It is pinned to a vertical wall at point B and supported by a uniform 15.9 kg diagonal brace that is pinned at point C on the beam and at point A on the wall.  [Use g = 9.80 m/s2.]

A uniform, 24.5 kg beam of length 2.90 m is hangin

There is a load W, with a weight of 211 N, hanging at the end of the horizontal beam. The distance BC is 2.17 m, and the distance AB is 1.63 m. (The distance BD is 2.90 m.)

(a) Draw a free-body diagram for the horizontal beam, showing only forces that act on the beam, using Cx and Cy for the components of the force acting at point C. Use torques about an axis at point B to solve for the vertical component of the force on the horizontal beam at joint C: (Use "+" if the force component is up, "-" if it is down.)
Cy =

(b) Draw a free-body diagram for the brace, including only forces that act on the brace. Use torques about the point A to solve for the horizontal component of the force on the diagonal brace at joint C: (Use "+" if the force component is right, "-" if it is left.)
Cx =

(c) Find the horizontal and vertical components of the force on the horizontal beam at the joint B. Use "+" for forces up or to the right, "-" for forces down or to the left.
Bx =  
By =

(d) Find the horizontal and vertical components of the force on the diagonal brace at the joint A. Use "+" for forces up or to the right, "-" for forces down or to the left.
Ax =  
Ay =

0 0
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Answer #1

s-avg IU a ㅋ11시. s yxq.SI Cy Taning moment about B 2. S1.43 1.bas 2.13 ement aboutA O For henizontal beam ey c γ : ayo.3y s +2,1 for the bnare Ay ะ-673 32 C To the Left

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