In a fluorescent tube of diameter 4.2 cm, 2 × 1018 electrons (with a charge of...
In a fluorescent tube of diameter 4.2 cm, 2 × 1018 electrons (with a charge of −e) and 1 × 1017 positive ions (with a charge of +e) flow in opposite directions through a cross- sectional each second.
What is the current in the tube? The fundamental charge is 1.602 × 10−19 C.
Answer in units of A.
Homework Answers
These charged particles move in opposite directions, thus their
contributions to total current are additive.
I = (2E18 + 0.1E18)*1.6E-19 = 0.336 A exactly
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