Question

1. Two circular metal plates. A and B, each of radius-= 0.150 m are placed parallel to each other a distance d = 0.070 mh apart as shown in the figure. The plates carry equal and opposite amounts of charge Q = 5.00 μ C with plate A carrying the positive charge. (a) Calculate the magnitude of the electric field between the plates. Give its direc- tion. (b) Draw five (5) electric field lines like you did in the lab. (c) If an electron is placed between the plates, calculate the acceleration imparted to the electron by the electric field. Give the direction of this acceleration. how long does it take it to reach plate A?

Answer 1

Radius of each metal place (r) = 0.15 m Distance (d) = 0.070 m. Area of the circular plate(A) = pi r^2 implies A = 22/7 (0.15)^2 implies A = 0.07071 m^2 Surface charge density of plate (sigma) = charge/Area = 5 times 10^-6 C/0.07071m^2 implies sigma = 70.711 times 10^-6 c/m^2 The electric field due to a place sheet of charge is uniform and do not depend upon the distance from the charge sheet. The electric field between the plates due to plate A is given by E_1 vector = sigma/2 element_0 The electric field between the plates due to plate B is given by E_2 vector = sigma/2 elementof_0 so, the net electroc field between the plates is given by E vector = E_1 vector + E_2 vector implies E vector = sigma/2 elementof_0 + sigma/2 elementof_0. E vector = sigma/elementof_0 The direction of electric field is from positive plate(A) to negative plates(B)