1:
Since population standard deviation is unknown and distribution shape is normal so t critical value should be sued.
Degree of freedom: df=n-1=4
The critical values of t are:
t-critical = +/- 2.776
Excel function used: "=TINV(0.05,4)"
2:
Since population standard deviation is unknown and distribution shape is normal so t critical value should be sued.
Degree of freedom: df=n-1= 10-1 = 9
The critical values of t are:
t-critical = +/- 2.262
Excel function used: "=TINV(0.05,9)"
3:
The sample size is less than 30 and population standard deviation is known so neither t nor z critical values can be used.
4:
The sample size is greater than 30 and population standard deviation is known so according to CLT sampling distributio of sample mean will be approximately normal. So z critical values can be used.
The critical values of z are:
z-critical = +/- 2.576
Excel function used: "=NORMSINV(1-(1-0.99)/2)" or "=NORMSINV(0.995)"
5:
Since population standard deviation is unknown and distribution shape is normal so t critical value should be sued.
Degree of freedom: df=n-1= 92-1 = 91
The critical values of t are:
t-critical = +/- 1.662
Excel function used: "=TINV(0.10,91)"
6:
The sample size is less than 30 and population standard deviation is known so neither t nor z critical values can be used.
7:
Population standard deviation is known and it is given that population is normally distributed so z critical values can be used.
The critical values of z are:
z-critical = +/- 2.33
Excel function used: "=NORMSINV(1-(1-0.98)/2)" or "=NORMSINV(0.99)"
8:
Since population standard deviation is unknown and distribution shape is normal so t critical value should be sued.
Degree of freedom: df=n-1= 37-1 = 36
The critical values of t are:
t-critical = +/- 2.434
Excel function used: "=TINV(0.02,36)"
2. Fill this table with the appropriate critical values from the normal (z) or Student'st(t) distributions,...
Identify the critical t. An independent random sample is selected from an approximately normal population with unknown standard deviation. Find the degrees of freedom and the critical t value t∗t∗ for the given sample size and confidence level. Round critical t values to 4 decimal places. Sample size, n Confidence level Degree of Freedom Critical value, t∗t∗ 22 90 11 95 3 98 20 99
(8 points) Identify the critical t. An independent random sample is selected from an approximately normal population with unknown standard deviation. Find the degrees of freedom and the critical t value t* for the given sample size and confidence level. Round critical t values to 4 decimal places. Sample size, n Confidence level Critical value, t* Degree of Freedom 12 90 28 95 4. 98 3 99
If sample size is 15, below please fill the UPPER and LOWER critical values of the standard normal distribution and t distribution under the various confidence levels. (20%) Confidence level standard normal distribution t distribution 80% _______________ _______________ 90% _______________ _______________ 95% _______________ _______________ 98% _______________ _______________ 99% _______________ _______________
1) (8 points) Identify the critical t. An independent random sample is selected from an approximately normal population with unknown standard deviation. Find the degrees of freedom and the critical t value ?∗t∗ for the given sample size and confidence level. Round critical t values to 4 decimal places. (8 points) Identify the critical t. An independent random sample is selected from an approximately normal population with unknown standard deviation. Find the degrees of freedom and the critical t value...
2. Critical Values from the t-table (Table D) (a) Accurate to the nearest 3 decimal places, what is the critical value (t or z*) that corresponds to the given confidence levels and degrees of freedom? Fill in the following table with the appropriate critical values from the t-table (table D). Remember to truncate down the df when the exact value is not listed in the table. a unknown (t) df- 12 df- 29 df 71 Confidence level σ known (r)...
(8 points) Identify the critical t. An independent random sample is selected from an approximately normal population with unknown standard deviation. Find the degrees of freedom and the critical t value t* for the given sample size and confidence level. Round critical t values to 4 decimal places. Sample size, n Confidence level Degree of Freedom Critical value, t* -1.4398 7 906 5 95 -2.1318 -2.2137 19 98 18 3992 99 -6.9646 Help Entering Answers Preview My Answers Submit Answers
Explain how to find the critical value, T* with a graphing TI-84 calculator. round critical t-Values to 4 decimal places (8 points) Identify the critical t. An independent random sample is selected from an approximately normal population with unknown standard deviation. Find the degrees of freedom and the critical t value t* for the given sample size and confidence level. Round critical t values to 4 decimal places. Critical value, t* Sample size, n Confidence level 19 9 0 24...
Do one of the following, as appropriate. (a) Find the critical value z Subscript alpha divided by 2zα/2 , (b) find the critical value t Subscript alpha divided by 2tα/2 , (c) state that neither the normal nor the t distribution applies. Confidence level 9999 %; nequals=1818 ; sigma is knownσ is known ; The population appears to be veryskewedvery skewed.
Do one of the following, as appropriate. (a) Find the critical value 2zα/2,(b) find the critical value 2tα/2, (c) state that neither the normal nor the t distribution applies. Confidence level 95%; n=18;σ is known; population appears to be very skewed. A. 2tα/2=1.740 B.zα/2=1.96 C.tα/2=2.110 D. zα/2=1.645 E. Neither or t distribution applies
1 (rport What are the critical values 2 30? and 2 that correspond to a 99% confidence level and a sample size of 13.121, 52.336 O13.787,53.672 O14.257,49.588 O 19.768, 39.087 2. A simple random sample of 8 reaction times of NASCAR drivers is selected. The reaction times have a(4 point) normal distribution. The sample mean is 1.24 sec with a standard deviation of 0.12 sec. Construct a 99% confidence interval for the population standard deviation. O 0.20 < σ <...