Homework Answers
Let us Assume
- address of object Rectangle p1 is 1000.
- address of object Rectangle p2 is 2000.
- address of object Rectangle p3 is 3000.
- address of variable area is 4000.
Each rectangle object contains variables length , breadth
After the first step Rectangle p1 = new Rectangle (30,45) . Constructor of the rectangle object is called and length variable of p1 contains 30 and width variable of p1 contains 45 and p1 will have address 1000.
After the second step Rectangle p2= new Rectangle (50,65) . Constructor of the rectangle object is called and length variable of p2 contains 50 and width variable of p2 contains 65 and p2 and p2 will have address 2000.
After the third step p2 = p1 now contents of p1 will be assigned to p2 i.e, length of p2 will be 30 and width will be 45 but address of p2 will remain same.
After the fourth step Rectangle p3 = p2 , p3 will be having address 3000 and length , width would be 50,65 respectively
After the fifth step int area = p3.getArea() ; variable area will contain length of p3 which is 50*65 = 3250 at the address 4000.
To represent the memory image we will be following this box notation where contents in the box contains variables of object and side of box contains address of the object.
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