Question

A pilot takes off from Amber Island and flies for 150 km at 040°T to Barter Island where she unloads her first cargo. She intends to fly to Dream Island, but a bad thunderstorm between Barter and Dream islands forces her to fly off-course for 60 km to Crater Atoll on a bearing of 060°T.She then turns on a bearing of 140° T and flies for 100 km until she reaches Dream Island, where she unloads her second cargo. She then takes off and flies 180 km on a bearing of 055°T to Emerald Island. b. From Emerald Island she flies directly back to Amber Island. How many kilometres did she travel on her return trip? Round to the nearest kilometre. Please answer part b.

Answer 1

180 km * dixestion displacement D 155 200km 40 2 boken I 150km A Too lion Here for finding final distance, the components of distances will be used. First fending X-direction distance le dx = AE dx = AB'+ B'cl-c'D' + D'E' AB' = 150 COS(40) = 314,9 km B'c' = Go cos(60) = 30 km c'D' = 100 cos(40) = 76.6 km D'E' = 180 cos (55) = 103.2 km dx = 114,9+30 76.6 + 103. 2 = 171.5 km AT D'B' d' E Simidardy dy - y -component of displacement. dy= AB" + B"c" y "D" +"E" AB" = 150 sin (40) = 96.44 km Bic" = 60 sim(60) = 51,9 km. d'o" - 100 sinuo) = 64,3 km V" E' = 180 sin(55) = 147.5 km - dy = 96,4 + 51.9 + 64,3 + 147.5 = 360.1 so osing vector formula. this distance between E and A is di d= dx² + dy² = √ (171,5)² + (360. 1² d=398.85 km or Id=399 km]