Question

Suppose we have two integer arrays with the same type, write an AL program to check whether or not there are two integers, one from each array, with sum equal to zero. If there are such integers exist, print out all such combinations to the console window, otherise, print out "No integers in these two arrays, one from each array, with sum equal to zero." to the console window. December 3. 2018 For example, suppose we have the following two integer arrays: arrayl QWORD-11,-3,7,8 array2 QWORD 2,7,3,3,-8, 11.-8 Clearly, we have integers from these two arrays, one from each, with sum equal to zero. Following is the list of tof CSC 221 (F18, Dr. Zuo e 2of 2 such combinations (which aslo should be the print out of your program): -3.3 3.3 8.-8 8.-8 However, if we have the following two arrays: arrayl QWORD 1, 3,7,8 array2 QwORD 2,7 Clearly, we do not have integers from these two arrays, one from each, with sum equal to zero. So your program should print out "No integers in these two arrays, one from each array, with sum equal to zero." You can use these two examples to check the correctness of your program. Similarly, I encourage you to test your program using multiple different arrays to make sure the correctness of your program. Note that try to use the TYPE and LENGTHOF operators to make your program as flexible as possible if the array size and type should be changed in the future

Answer 1

#include <stdio.h>  

#include<math.h>

void main()  

{  

int arr[10],arr1[10];

int i;  

printf("-----------------------------------------\n");

  

printf("Input 10 elements in the array :\n");  

for(i=0; i<10; i++)  

{  

printf("element - %d : ",i);

scanf("%d", &arr[i]);  

}  

for(i=0; i<10; i++)  

{  

printf("element - %d : ",i);

scanf("%d", &arr1[i]);  

}  

for(I=0:I<10;I++)

{

for(j=0;j<10;j++)

{

if(arr[I]==abs(arr1[j]))

{

printf("%d,-%d",arr[I],arr[I]);

}

}

}

}

Here I used the array size of each 10....you have to just modify the length of the array....the main logic is correct....

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