a)
Repeated measure ANOVA will be used
...........
b)
Anova: Two-Factor With Replication | ||||||
SUMMARY | 4 hours sleep | 8 hours sleep | Total | |||
50mg caffiene | ||||||
Count | 7 | 7 | 14 | |||
Sum | 60 | 86 | 146 | |||
Average | 8.571429 | 12.28571 | 10.42857 | |||
Variance | 1.619048 | 2.904762 | 5.802198 | |||
100mg caffeine | ||||||
Count | 7 | 7 | 14 | |||
Sum | 79 | 82 | 161 | |||
Average | 11.28571 | 11.71429 | 11.5 | |||
Variance | 4.238095 | 3.238095 | 3.5 | |||
Total | ||||||
Count | 14 | 14 | ||||
Sum | 139 | 168 | ||||
Average | 9.928571 | 12 | ||||
Variance | 4.686813 | 2.923077 | ||||
ANOVA | ||||||
Source of Variation | SS | df | MS | F | P-value | F crit |
Sample | 8.035714 | 1 | 8.035714 | 2.678571 | 0.114755 | 4.259677 |
Columns | 30.03571 | 1 | 30.03571 | 10.0119 | 0.004188 | 4.259677 |
Interaction | 18.89286 | 1 | 18.89286 | 6.297619 | 0.019242 | 4.259677 |
Within | 72 | 24 | 3 | |||
Total | 128.9643 | 27 |
F stat for caffiene =2.67
p value = 0.11
p avlue > 0.05 , not significant
so, there is no main effect of caffiene
................
c)
F stat for hours sleep= 10.012
p value =0.004
p value < 0.05, significant
so, there is main effect of hours of sleep
8 hours sleep have larger score
................
d)
F stat for interaction = 6.297
p value = 0.019
p value < 0.05, significant
so, there is an interaction between 2 factors
................
THANKS
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