Question
Intepret all results at the .05 singificance level
2. In order to better prepare for her 8:00am classes, a statistics graduate student designs an experiment to see how various
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Answer #1

a)

Repeated measure ANOVA will be used

...........

b)

Anova: Two-Factor With Replication
SUMMARY 4 hours sleep 8 hours sleep Total
50mg caffiene
Count 7 7 14
Sum 60 86 146
Average 8.571429 12.28571 10.42857
Variance 1.619048 2.904762 5.802198
100mg caffeine
Count 7 7 14
Sum 79 82 161
Average 11.28571 11.71429 11.5
Variance 4.238095 3.238095 3.5
Total
Count 14 14
Sum 139 168
Average 9.928571 12
Variance 4.686813 2.923077
ANOVA
Source of Variation SS df MS F P-value F crit
Sample 8.035714 1 8.035714 2.678571 0.114755 4.259677
Columns 30.03571 1 30.03571 10.0119 0.004188 4.259677
Interaction 18.89286 1 18.89286 6.297619 0.019242 4.259677
Within 72 24 3
Total 128.9643 27

F stat for caffiene =2.67

p value = 0.11

p avlue > 0.05 , not significant

so, there is no main effect of caffiene

................

c)

F stat for hours sleep= 10.012

p value =0.004

p value < 0.05, significant

so, there is main effect of hours of sleep

8 hours sleep have larger score

................

d)

F stat for interaction = 6.297

p value = 0.019

p value < 0.05, significant

so, there is an interaction between 2 factors

................

THANKS

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