Question

step 2) trial #1 mass of solid standard (KHP, potassium hydrogen phthalate) used = 0.100g; trial 1 equivalence point = 35.32 mL

step 5) mass of unknown (mixture of KHP and NaOH) = 1.5389g; trial #1 equivalence point = 10.50 mL

find requested weight percent

What happens in step 2) Use a convenient size flask and prepare an aqueous solution containing a known mass of KHP that will react with an estimated 25 mL of the unstandardized NaOH solution. (the flask will be a 100 mL volumetric flask)

What happens in step 5) Your unknown solid is a mixture of KHP and NaCl. Record the mass of the unknown and place it in a 100 mL volumetric flask. Dissolve your unknown in DI water then dilute to the mark. Sonication will speed dissolution. Perform four 25 mL titrations of the unknown solution with your standardized NaOH. On your first titration of the unknown, you may want to get a "rough" titration to get an idea where the endpoint lies. Calculate the weight percent of KHP in your unknown solid.

How to I find the weight percent given the above information (the equivalence point and masses obtained)?

Answer 1

Step at KHP & NOOH ktuator +4o. moles of WP 2 moles it wast 0-100g 2 mxy Nach 204-225 mol 0.000489 moles 2 mach x 3532 m2 X ) molarity of – Standardized woon. 10-0139 m) stepst moles moles of KCHP of KHP 2 2 moles of nach 0.0139m x 10.50m. te 163 m. . o-ooo146 moles

In 25ml Saurono solution, moles & KHP 0-oool46 moles In 100 ml Solution, moles of HPP 20-o0ol 46 moles x 100 mass of MOI KHP 2 2 percent weight of 2 0.000584 moles. 0.000584 moles x 204-229 0.119269 KHP a mass of KCHP & 1007. mass of mixture 2 0-1999 t53899 27-757. X007