Question

edu/courses/93226/files?preview=10921095 4 Evaluate the following Case II type integral Jox ③ ure partial the no substitution and fractions to integrate following a) / text tex)

Answer 1

Aply un substitution user . ducende dx = h du = 5 celu dlowy = Jevtulemu) i due ezu] Take the partial fraction of usw.law i = A (4+1)(4+ 2) +Blu} (u+ 2) + c(u)(u+1) U=-2 Urol U=0 2cal 2A=1 Aay -Ba| Bal C= 2 = ) A tu hate the fate di =ja du tj ne du + J atute, du uye the common inlegral st du = ln Luj sa te dua lnfutil Ut Jute du = ln lutal

Take the Constant out = fut du + J Letz dut & Jt du = -ln (kets + t In (utz | + z ln 14) substitute back user =- ln lentila z ln lent21 + 2 dule") - lu le til at du lental & Eik ť tlmle" l = 2x Add a constant to the solution en la le'+11+<lade2/+ų 2 + Thank you