Three blocks on a frictionless surface are connected by massless strings, with M1 = 1.50 kg, M2 = 2.60 kg, and M3 = 3.40 kg. Due to the force F acting on M3, as shown, the system accelerates to the right. Given that T1 is 3.10 N, calculate T2
assuming that the system is something like this
M1-----T1------M2-----T2------M3----F
since the acceleration of all the blocks are the same, let it be a.
T1=M1*a
or a=3.1/1.5
=2.0667
for the block 2,
T2-T1 = M2*a
or T2 - 3.1 = 2.6*2.0667
or T2=8.47 N
Three blocks on a frictionless surface are connected by massless strings, with M1 = 1.50 kg,...
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