Question

A corporation that maintains a large fleet of company cars for the use of its sales staff is interested in the mean distance driven monthly per sales person. The following table gives the monthly distances in miles driven by a random sample of 17 sales persons 1990, 2214, 2036, 2306, 1987, 2496, 2073, 2398, 2203, 2480, 1886, 2588, 1862, 2077, 2103, 2403, 2469 Send data el Based on this sample, find a 90% confidence interval for the mean number of miles driven monthly by members of the sales staff, assuming that monthly driving distances are normally distributed. Then complete the table below. Carry your intermediate computations to at least three decimal places. Round your answers to one decmal place. (If necessary, consult a list of formulas.) What is the lower limit of the confidence interval? What is the upper limit of the confidence interval? X ?

Answer 1

SATURDAY 8 9 10 11 12 13 15 16 17 22 23 24 25 26 27 29 30 15 16 17 18 19 20 Answeg).... .......Pales) Zoll27. Pales) 28/10/2019 = 17 Sales person 19908814, 80368306., 1987' 249.6., 8073,2398, 2003, 2480) 1886, 85.88, 1862, 20.77., 2103 2403, 246.90 X = 9210.059.... Man ...Sd = 230.343 tacat 1.746 at df = 1-1=17-1=16 f alpha=0.10 tal2= tolol2 60.05 Margin of coma = E= st*tc/system) = 9301343 * 1.746 402.178878 .. FIT 4.1831056256 =97. 543 90.4. CJ = (-2, X+8) (2210.069–97.543, 2210-059797.543) (2112.516, 2307.602) lowey limit = 2112.5 uppen mit 2307.6