Homework Answers
We know for a torsional pendulum,
Time period T = 2pi * sqrt(I/mgR)
[T/2pi]^2 = I/mgR
[0.80/(2pi)]^2 = I/[0.93*9.8*0.09]
I = [0.80/(2pi)]^2*[0.93*9.8*0.09]
= 0.013 kgm^2 answer
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A coat hanger of mass m = 0.248 kg oscillates on a peg
as a physical pendulum as shown in the figure below. The distance
from the pivot to the center of mass of the coat hanger is
d = 18.0 cm and the period of the motion is T =
1.16 s. Find the moment of inertia of the coat hanger about the
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