Question

Homework 3: Due 2/4 30 Points Problem 1 At halftime of a football game, souvenir balls are thrown with a velocity vo to the spectators in the upper seats. The cheerleader releases the ball a = 6 ft high at an angle 0 = 50° and b = 30 ft from the front edge of the stands, which is c = 5 ft tall. The stands are angled upward as B = 30°, and the lower target point B is d = 50 ft from the front edge and e = 30 ft from the back edge C, as measured along the sloped side. Determine the range of values of vo if the balls are to land between points B and C. Problem 2 Four seconds after automobile B passes through the intersection shown traveling south at Ve = 75 mph, automobile A passes through the same intersection at va = 65 mph. The speed of each automobile is constant. The angle between roads is 8 = 60°. Determine: the relative velocity (in mph) of B with respect to A.

Answer 1

The range of values of V0 is 49.15 ft/sec less than V0 less than 69.86 ft/sec. You can change foot into metre as well.
B Vo yo & Uno Molas (645 K 30+ -- At Point B » doriental motion: x = Vaso *ta xp = 30ft + So 16330 Vno Volas solo 30+ Solas so rolossoxto VoxtB = 30 750 casa. - 73.3. 114.53 Lesson ft-See. 0.64 Vertical motion up to B Y = "yox tВ - 2 g +² So sin 300 l = vo Simso tz - 32.18 + - g inst/232.18) sutst ① in ② -0.5 = (0.76) (114.53) - 16.075 to 16:075 to 96.6440.5 to = 5.42 in A from ☺ Tvo= 49.15 t/sec)

Similialy at point c e ů Vnox to te is tome to reache) 7 = 30 + Bols & 30° Vo = o las soo 30 + 80 (es3oo Vocas soo x te Voxtes 30 70 80 casso casso o Nox tc. = 99.3 - 155.1 ft see 0.64 for vortical motion uptoc Ye = lyo xte - /gter Po Sim 30 -1 = Vosinsooxte -1 (3.10) +E 39 = txt X. (0.766) - 16.09 x te 39 - Cat (155.1).x(0.766) - 16.09xte using ang 16.09 to 118.0-39 te = 79.8066 - 4.960 - 16.09 te = 2.22 0 4 using ☺ Vo = 69, 86 ft/sect in from ② x range of Von 49. 158t/secco L 69.86 ft