the reaction is
HClO4 + KOH KClO4 + H2O
1 mole of HClO4 reacts with 1 mole of KOH
Consider the titration of 25.0 mL of 0.050 0 MHClO_4 with 0.100 M KOH. Find the...
Consider the titration of a 25.0 mL sample of 0.100 M HCl with 0.200 M KOH. The volume of equivalence is 12.50 mL. (Remember to report pH values with two places past the decimal point.) A)What is the pH of the sample before any KOH is added? B)What is the pH after 9.00 mL of KOH have been added? C)What is the pH at the equivalence volume? D)What is the pH after the addition of 14.0 mL of KOH?
Consider the titration of 40.0 mL of 0.200 M HCIO4 by 0.100 M KOH. Calculate the pH of the resulting solution after the following volumes of KOH have been added. a. 0.0 mL pH = b. 10.0 mL pH = c. 60.0 mL pH = d. 80.0 mL pH = e. 110.0 mL pH = Consider the titration of 100.0 mL of 0.200 M acetic acid (Ka = 1.8 x 10-5) by 0.100 M KOH. Calculate the pH of the...
Consider the titration of 50.0 mL of 0.100 M HC3H5O2 by 0.100 M KOH for the next five questions (Ka for HC3H5O2 = 1.3 x 10-5). Calculate all pH values to two decimal places. - Calculate the pH after 25.0 mL of KOH has been added?
Consider the titration of 25.0 mL of 0.100 M HF with 0.125 M KOH. The Ka is 6.8 x 10-4 for HF. What is the pH after 20.0 mL of base are added? Please show steps.
Consider the titration of 40.0 mL of 0.200 MHCIO by 0.100 M KOH. Calculate the pH of the resulting solution after the following volumes of KOH have been added. a. 0.0 ml pH = b. 10.0 ml pH = c. 70.0 ml pH = d. 80.0 mL pH = e. 130.0 ml pH =
Consider the titration of the titration of 50.0 mL of 0.100 M acetic acid (HC2H2O2) with 0.100 M. The pka = 4.76. d. Determine the pH after 50.0 mL of titrant (NaOH) have been added. This is the equivalence point. All of the acid has been converted to its conjugate base, pH is determined by the equilibrium for the conjugate base
Consider the titration of 50.0 mL of 0.0500 M H2NNH2 (a weak base; Kb = 1.30e-06) with 0.100 M HIO4. Calculate the pH after the following volumes of titrant have been added: (a) 0.0 mL (b) 6.3 mL (c) 12.5 mL pH = DHO pH = (d) 18.8 ml (e) 25.0 ml (0) 37.5 mL pH = 0 pH = pH -
A student performs a titration of 25.0 mL of 0.100 M lactic acid (HC3H5O3), using 0.050 M sodium hydroxide (NaOH). The Ka for lactic acid is 1.4 x 10-4. a) (10 points) What is the pH of the solution after the addition of 23.5 mL of sodium hydroxide solution? b) (4 points) How many milliliters of NaOH are required to reach the equivalence point? c) (4 points) Write the chemical reaction that will determine the pH of the solution at...
. 20.0 mL of 0.100 M lactic acid solution is titrated with 0.100 M NaOH solution. Calculate the pH of the contents of the Erlenmeyer flask at each of the following points during the titration. (a) When 0.00 mL of NaOH have been added. (2) (b) After 5.00 mL of NaOH have been added. (3) (c) After 20.0 mL of NaOH have been added. (3) (d) After 10.0 mL of NaOH have been added. (1) (e) After 25.0 mL of...
Consider the titration of 60.0 mL of 0.0400 M C6H5NH2 (a weak base; Kb = 4.30e-10) with 0.100 M HBr. Calculate the pH after the following volumes of titrant have been added: Consider the titration of 60.0 mL of 0.0400 M C H5NH2 (a weak base; Kb = 4.30e-10) with 0.100 M HBr. Calculate the pH after the following volumes of titrant have been added: (a) 0.0 mL (C) 12.0 mL (b) 6.0 mL pH = pH = x pH...