Question

11. Use the data given to calculate the entropy and enthalpy changes for the combustion (burning in the presence of oxygen) of 1 mole of CoHat 25°C to form carbon dioxide (gas) and water vapor Calculate A Hºrxn, AS rxn, and AGºrxn and determine if the combustion is spontaneous or non-spontaneous Chemical Species H2O (9) Entropy (J/moleK) 188.8 173.4 213.8 205.2 Enthalpy (kJ/mole) -241.8 49.1 -393.5 C6H6 (1) CO2(9) O2 11_CH. (1) + |__7.5__02 (3) 6 CO2(g) + _3_H208) 11.11 242 Lat 299 OK

Answer 1

C6H6192 + 7.5 ₂ 6 co 6 CO₂ + 3H₂O Calculating enthalpy Change Arxn En DH reactat Em AH product - (6 x 4 vo + 3x AH..) - AHċette + 705440,7 = 6*1(-39.5) + 3x (-24118) - (49.1.+0) { Aheo, 301 49.1 - 2361 785.4 - 3135.5 KJ/mole Now Calculating Entropy change. AS n = {nas product En 4s reacfent ( 6x Sex + 3x SºH50) - (SE + 7:55) = (6x 21318 + 3 * 188.8 (173.4 + 7.5x205-2 a (1282.8 + 566.4) - ( 173.4 + 1539) 136:8 J/moleki Now A9rxna A HO TAS 3135.5 kJ/mole 298 × 136.8 8 kJ / make 1000 4007 - 3135.5 - 40.7669 - 3176.2664 KJ/mole

Hence, For fue ginen reaction, A HOS 3135:5 kJ/mole A Sorens 136.8 Jlncolok A Gren 3176.2664 kJ/mole As, Agren is negative, the reaction is Spontaneous in nature.