If A=log 3(15), B=109 15(45), C =log 45(81), then value of the expression: A.B.C is 1...
NATION Identify the property used to find the equivalent expression. Part A a.b.c=c.b.a Select a Value Part B (n + 7) + 6 = n + (7 + 6) Select a Value Part -15m(x + y) = -15mx-15my Select a Value Part D (14.n).(-3) = -3. (14.n) Select a Value Part E 11 + 3 + x + 5 = x + 11 + 3 + 5
find the simplified boolean expression of X = (A'.B'.C'.D)+(A'.B'.C.D')+(A'.B'.C.D)+(A'.B.C'.D)+(A'.B.C.D)+(A.B'.C.D)+(A.B.C'.D)
9. 16 Find the approximate value of the expression log 160. a) 0.54 b) 1.83 c) 2.20 d) 10
Q9: Simplify without using a calculator. a) log (64) b) log,(1/3) c) log/2(32) d) log(.00001) Q10: Which statement is true? Make corrections to any of the false statements. a) log (x+y) = log.x+logay b) log.(x/y) = log x/logay c) The statement 39=p is equivalent to q=p. Q11: Use properties of logarithms to expand the expression xVx+3 (x+3) as much as possible. In
6. Solve for x log2 (x + 7) + log 2x-3. a) x+7=3 b) 1 c) not possible x d) none of these 7. Evaluate log, a) x b) c) not possible d) none of these 8. What is the solution of -764? a) -2 b) 0 c) 2 d) 10 9. Find the approximate value of the expression log 16 160 a) 0.54 b) 1.83 c) 2.20 d) 0.9 10. Find the value of the expression 2.5 b) 12.2...
a) Rewrite the expression in log form. 10* = 15 b) Rewrite in exponential form. In x = 8 I
4. Given : 81 a Rewote the expression as a radical b. Simplify ( 81
Use log, 3 * 0.583, log, 5 0.821, and log, 7. 1.064 to approximate the value of the given logarithm to 3 decimal places. Assume thath > 0 and b + 1. log) 21 5. Write the logarithmic expression as a single logarithm with coefficient 1, and simplify as much possible. Assume that all variable expressions represent positive real numbers. log, (v) + log2 (x2 - 9) – log2 ( +3) - Write the logarithmic expression as a single logarithm...
Question 1 The value of the expression c = a + b--, assuming a, b, and c are integer variables and a 3 and b-4.is C = 7; b=4 none of the answers is correct C-7;b = 3 O c = 6; b = 3 Note
Each) log 4 (x - 3) = -1 4=x-3 13 13 +3 3= 13 Answer: b.) 6 In 6x = 30 %3D in6X %3D Answer: c.) +10970x +10g|0x log 10 (x + 30) = 3 – log 10 × check 10910 (20+30)= 3:-, 10910 20 10910130)=-10gio (20)13 10giol 50) +10910(20) = 13 to 10910( 50.20) = 103 10910 (Xt30) †109 10X = 3 (V130)(X) = 3 109 %3D T000 1000 (X7 30)X) = 10 X- 20 Answer: