Question

Physics 211 Test Five Spring 2018 Name A disc is supported so that it freely rotates 10 kg and a radius nf Physics 211 Test Five Spring 2018 A boom 37 degrees above the horizontal is supported by a fixed support in the wall. The boom is 5 meters long and has a mass of 10 kg. If the horizontal component of the wall support is determined to be 8 N directed horizontally to the right and the tension in a cable attached to the free end has a force of 10 N, what angle is the cable directed back to the wall? Draw the free body diagram. Sum forces and torques and set equal to zero. What is the reactive torque at the wall? 37 What is the vertical reaction at the wall? How far above the boom is the cable attached to the wall?

Answer 1

Tau = (5/2 (10g)(cos 37 degree)) - (5 T sin(37 + phi)) sigma F_y = H_y - 10g + 10 sin phi = 0 sigma F_x = H_x - T cos phi = 0 8 - 10 cos phi implies 0 implies phi = cos^- 1(8/10) phi = 36.7 degree H_y = (10 times 3.8) - (10 sin 36.7) implies H_y = 32 N torque, tau = (5/2 times 10 times 3.8 times cos 37 degree) - (50 sin(37 + 37)) tau = 147.6 N.m \r\n x_1 = x_2 = 5 sin 37 degree x_1 = x_2 = 3 m x = x_1 + x_2 = 6m rightarrow Ans