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Constants Find the kinetic energy K of the car at the top of the loop. Express your answer numerically, in joules. (Figure 1)

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® E-mah - 50(9-8)(48) = 23520 J. P= 50x9.8 (a x16) = 15680 J. ke = E-P=784015 mgto VERS mv 2 mg etot sa mge +mg(ar)- Emgr #=

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