Question

I don’t understand can you help

5. Given the definition and code fragment: (2 points int matrix[2]13]; int k = 0; for(int i =0; i < 2; i++) for (int j=0, j < 3 ) matrix[i]lj]-k++; The value of matrix[1][1] is

Answer 1

Above program denotes how many matrix elements need to be crossed to get our required adress.

For example to get a[1][1] we need to get 4 matrix elements like a[0][0], a[0][1], a[0][2], a[1][0]

Program in execution:

K=0;

a[0][0]=k++=0 We need to cross 0 matrix elements.

a[0][1]=k++=1 We need to cross 1 matrix elements.

a[0][2]=k++=2 We need to cross 2 matrix elements.

a[1][0]=k++=3 We need to cross 3 matrix elements.

a[1][1]=k++=4 We need to cross 4 matrix elements.

a[1][2]=k++=5 We need to cross 5 matrix elements.

After Execution:

a=[0,1,2

      3,4,5]

********************************************Other way******************************************

It is also used to find address of our element as our array stored in row major orde.

Row major order:

assume matrix a of order m*n where m is number of rows and n is nummber of columns.

If starting indices of a is 0,0: (Assuming that each integer takes one memory location)

       address of a[i][j] = i*n + j

here a is of order 2*3 i.e. 2 rows and 3 columns and starting with indices 0,0.

       address of a[1][1] = 1*3 + 1 = 4

This array would be stored as follows.

Address	Value
0	a[0][0]
1	a[0][1]
2	a[0][2]
3	a[1][0]
4	a[1][1]
5	a[1][2]

Final answer is a[1][1]=4