A 0.320-kg block of a pure material is heated from 20.0°C to 65.0°C by the addition...
A 0.320-kg block of a pure material is heated from 20.0°C to 65.0°C by the addition of 2.88 kJ of energy. Calculate its specific heat. I got 200 but that is not the right answer and it needs to be in kJ/(kg · °C)
Homework Answers
Heat added,
Q = m*c*delta_T
delta_T=65-20 =45 C
m=0.320 kg,
Q=2.88 *10^3 J
2880=0.320*c*45
c=200 J/kg*k
=0.2 KJ/kg*k (Specific heat is 0.2Kj/kgk not 200 KJ/kgk)
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