Question

2. Rectifier with zener diode Given: Simple AC powered voltage reference source with following parameters: D1...D4 R1 Vout Vin SEC V sec=10 V (RMS) fset=60 Hz Vp=0.6 V (each) ZD=5.6 V / 10 mA C= 10 uF VREF= 5.6 V ☆ Calculate: R1 V Ripl

Answer 1

Solulit' - Coven VSEC = LOVERMS ANET=CoH3 Vo=0.6V (each) ZD= 5.6 v/10mA, CI=10uF, VREE = 5.6v. foom the Ciotuit ... R = Vemin-V2. - V212min 2min when Vanin can be calculated as Kemin = Vsee - [Vou +VD2. + VD3+V04 ) = 10-[0.6+0.6+06+0.6) => 10-2.4. V [min = 7.60. V20= 5.6V, V2=10-2. Izmin = 10mA . 76-5.6-lorom 19 - loma l R=190-2 Tom by Vaipple = V meals V peaks = VRny X 2 = 10x15 peaks = 4.140

Vsipple = 6 14 18 1out tino i Vsipple - 614.14 wandton n Voipple => 6. 20v. Resistance value of given circuit is 190 & sipple Voffage value is '6.200"