![19,915g 7. Calculate the theoretical percent water in the hydrate. [10 pts.] Note: The theoretical formula for the hydrate is](http://img.homeworklib.com/questions/ac00de70-7f09-11eb-bcc4-055622d9c977.png?x-oss-process=image/resize,w_560)
Homework Answers
Data required
Molar mass of Water ( H2O ) = ( 2 
1.0079 ) + ( 16.00 ) = 18.02 g / mol
Molar mass of MgSO4. 7H2O = 24.31 + 32.06
+ ( 4
16.00 ) + 7 ( 18.02 ) = 246.51 g / mol
Calculation of theoretical % of hydrate in MgSO4. 7H2O
1 mole MgSO4. 7 H2O contain 7 moles of H2O.
Therefore, mass of water present in 1 mole of MgSO4.
7H2O = 7
mass of Water
mass of water present in 1 mole of MgSO4.
7H2O = 7
18.02 g = 126.14 g
% of water in MgSO4. 7H2O =[ Mass of water / Mass of MgSO4. 7H2O ] 100
% of water in MgSO4. 7H2O = [ 126.14 g / 246.51 g ] 100
% of water in MgSO4. 7H2O = 51.17
ANSWER : Theoretical % of water in MgSO4. 7H2O = 51.17
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